SoonerNorm
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I used to work on Trajectory applications for Space Shuttle so I have some idea of how this works . In the most basic view, t = √(2h/g) is always the correct answer but there is some discrepancy when adding a horizontal component. I'll explain in a minute. The best long jumper is the one who is very fast (thus distance through the air before gravity pulls him to earth) and one who can get very high (vertical height thus taking gravity longer to return him to earth). So, if one jumps exactly straight up, the longest hang time is the person who can jump the highest. However (here's the rub), if the force used to jump upwards is modified to an angle (horizontally if you will), the hang time will really depend on how long it takes to reach the highest point (and thus gravity will return him (it in the case of a football being kicked) to earth. So a football kicked downfield 40 yards that reaches its highest point 30 yards downfield (and thus took longer to reach its highest point) will spend more time in the air than one which is kicked 5 yards downfield but has the same highest point as the former (confused yet ).
All that being said, if one thinks of hang time as the person with highest vertical jump or footbal kicked the highest, he's going to be right almost all the time.
I guess you do have to be a physicists or a rocket scientist to understand all of this. Glad to have you and Banjo help out where some of us didn't really know where to start.